x^2+17x+289/4=0

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Solution for x^2+17x+289/4=0 equation: 



x^2+17x+289/4=0

We multiply all the terms by the denominator


x^2*4+17x*4+289=0

Wy multiply elements

4x^2+68x+289=0

a = 4; b = 68; c = +289;
Δ = b2-4ac
Δ = 682-4·4·289
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-68}{8}=-8+1/2$

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